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    Chemistry Problems: Glucose and Ethanol

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    1. C6H12O6= 2C2H6O+2CO2
    a. How many moles of glucose are required to produce 185 g of ethanol?
    b. How many grams of ethanol would be formed from the reaction of 0.325kg of glucose?

    2. Person contains 60% water by mass. If a person weighs 60 kg, how many moles of water are present in this person's body?

    © BrainMass Inc. brainmass.com October 5, 2022, 2:21 am ad1c9bdddf
    https://brainmass.com/chemistry/stoichiometry/chemistry-problems-glucose-and-ethanol-431317

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    1. C_6H_12O_6 → 2C_2H_6O + 2CO_2
    a. How many moles of glucose are required to produce 185 g of ethanol?

    Converting mass of ethanol to mole:
    185 g C_2H_6O x [1 mole C_2H_6O / 46 g] = 4.022 mole C_2H_6O
    Solving for mole of glucose:
    4.022 mole C_2H_6O x [1 mole C_6H_12O_6 / 2 mole C_2H_6O] = 2.011 mole C_6H_12O_6

    b. How many grams of ethanol would be formed from the reaction of 0.325kg of glucose?

    Converting mass in kg to gram:
    0.325 kg x (1000 g / 1 kg) = 325 g glucose
    Solving for mole of glucose:
    325 g C_6H_12O_6 x [1 mole C_6H_12O_6 / 180 g] = 1.806 mole C_6H_12O_6
    Solving for mole of ethanol:
    1.806 mole C_6H_12O_6 x [2 moles C_2H_6O / 1 mole C_6H_12O_6] = 3.61 mole C_2H_6O
    Converting mole ethanol to gram ethanol:
    3.61 mole C_2H_6O x (46 g / 1 mole C_2H_6O) = 166.11 g C_2H_6O

    2. Person contains 60% water by mass. If a person weighs 60 kg, how many moles of water are present in this person's body?

    Computing for mass of water:
    Mass of H_2O = 60 kg (0.60) = 36 kg H_2O
    Converting to mole:
    36 kg H_2O x (1000 g / 1 kg) x (1 mole H_2O / 18 g) = 2000 moles H_2O

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    © BrainMass Inc. brainmass.com October 5, 2022, 2:21 am ad1c9bdddf>
    https://brainmass.com/chemistry/stoichiometry/chemistry-problems-glucose-and-ethanol-431317

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