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Balancing and Limiting

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Balance the following equation: UF5 + H2O = UO2F2 + UF4 + HF
a) What is the maximum amount of UF4 that can be made from the 10.5 gms of UF5 and 5.0 gms of H2O
b) How much of which reactant is left after the reaction stops?

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Solution Summary

The maximum amount in an equation are given. The expert determine what reactant is left after the reaction stops are given.

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UF5 + H2O --> UO2F2 + UF4 + HF

Balancing the reaction, we get

1) 2UF5 + 2H2O --> UO2F2 + UF4 + 4HF

a) We see that 2 moles of UF5 react with 2 moles of water to give 1 mole of UF4.

Number of moles of UF5 = ...

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