Given % yield, calculate grams obtained
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Balance the following equation:
AsF3 + CCl4 ---> AsCl3 + CCl2F2
the theoretical yield of CCl2F2 = 1.68 moles
if the actual yield was 74.3% in the reaction, how many grams of CCl2F2 were obtained
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First write the balanced equation (even though you don't really use it here):
2AsF3 + 3CCl4 = 2AsCl3 + 3CCl2F2
Here you need to identify the differences ...
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