A chemist ran the reaction CH3CH2Cl(l) + KOH(aq) ^ CH3CH2OH(l) +KCL(aq) by heating 47.2 grams of CH3CH2Cl with excess KOH and obtained a yield of 28.7 grams of CH3CH2OH. What was his % yield?
I do not know where to begin with this problem. It only gives grams of one reactant? What is the actual yield? Detailed step by step instructions please.© BrainMass Inc. brainmass.com December 19, 2018, 8:46 pm ad1c9bdddf
The mass of the given reagent indicates that it is the limiting reagent, and the one that you base the theoretical yield on.
Find moles of CH3CH2Cl m/MM and then since it ...
This solution is provided in 141 words. It discusses how to find the percent yield using moles and the limiting reagent.