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    Energy of electrons

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    An electron microscope employs a beam of electrons to obtain an image of an object. What energy must be imparted to each electron of the beam to obtain a wavelength of 10.0pm? Obtain the energy in electron volts (eV) (1eV= 1.602x10^-19J )

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    The de Broglie equation is:
    lambda =h/(mv)=h/p

    lambda =wavelength= 10.0 pm = 10x 10^-12 m
    h= Planck's constant= 6.6261x 10 ^(- 34) J ...

    Solution Summary

    In this solution, we calculate the energy that must be imparted to each electron of the beam of electrons in an electron microscope to obtain a wavelength of 10.0pm.