An electron microscope employs a beam of electrons to obtain an image of an object. What energy must be imparted to each electron of the beam to obtain a wavelength of 10.0pm? Obtain the energy in electron volts (eV) (1eV= 1.602x10^-19J )© BrainMass Inc. brainmass.com February 24, 2021, 2:23 pm ad1c9bdddf
The de Broglie equation is:
lambda =wavelength= 10.0 pm = 10x 10^-12 m
h= Planck's constant= 6.6261x 10 ^(- 34) J ...
In this solution, we calculate the energy that must be imparted to each electron of the beam of electrons in an electron microscope to obtain a wavelength of 10.0pm.