# I AM TRYING TO FIND THE ACTIVATION ENERGY

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I AM TRYING TO FIND THE ACTIVATION ENERGY

My slope is (-4295.5)

My R is the Gas constant=8.314

How do I utilize the Arrhenius formula to get the Activation energy? Also, how do I calculate th slope of log K compared to 1/Temp?

Â© BrainMass Inc. brainmass.com December 24, 2021, 6:35 pm ad1c9bdddfhttps://brainmass.com/chemistry/chemical-kinetics/trying-find-activation-energy-124580

## SOLUTION This solution is **FREE** courtesy of BrainMass!

This is called an Arrhenius plot where you plot lnk vs. 1/T to get the activation energy. The reference could be found here:

http://en.wikipedia.org/wiki/Arrhenius_equation

The equation is:

lnk = lnA - (Ea/R)*(1/T)

This means the slope of your plot is = -Ea/kb

where kb is the Boltzmann constant.

So plot out the values as in the attached excel file. Using the fitting trendline feature, you arrive with the slope = -4295.5

Thus -4295.5 =-Ea/8.314

Ea = 35,712 (J/mol)

https://brainmass.com/chemistry/chemical-kinetics/trying-find-activation-energy-124580