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I AM TRYING TO FIND THE ACTIVATION ENERGY

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I AM TRYING TO FIND THE ACTIVATION ENERGY
My slope is (-4295.5)
My R is the Gas constant=8.314

How do I utilize the Arrhenius formula to get the Activation energy? Also, how do I calculate th slope of log K compared to 1/Temp?

https://brainmass.com/chemistry/chemical-kinetics/trying-find-activation-energy-124580

SOLUTION This solution is FREE courtesy of BrainMass!

This is called an Arrhenius plot where you plot lnk vs. 1/T to get the activation energy. The reference could be found here:
http://en.wikipedia.org/wiki/Arrhenius_equation

The equation is:
lnk = lnA - (Ea/R)*(1/T)
This means the slope of your plot is = -Ea/kb
where kb is the Boltzmann constant.

So plot out the values as in the attached excel file. Using the fitting trendline feature, you arrive with the slope = -4295.5
Thus -4295.5 =-Ea/8.314
Ea = 35,712 (J/mol)

This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!