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Rate Constants and Activation Energy

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The rate constants of some reactions double with every 10 degree rise in temperature. Assume that a reaction takes place at 336K and 346K. What must the activation energy be for the rate constant to double as described?

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Okay, I am attaching the worked problem in both a Word ...

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The activation energy is determined so that the rate constant to the reaction will be doubled from 336K to 346K.

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Determining Activation Energy from Rate Constant

Here is the problem I have to solve:
If 10 g of pure carbonic anhydrase catalyzes the hydration of 0.30 g of carbon dioxide in 1 min at 37 degrees C under optimal conditions, what is the turnover number (kcat) of carbonic anhydrase (in units of min-1)?

I have already calculated the turnover number, which is 2.0 x 107 min-1, but I'm kind of lost with two other questions.

(b) From the answer in (a) calculate the activation energy of the enzyme catalyzed reaction (in kJ/mol)
(c) If carbonic anhydrase provides a rate enhancement of 107, what is the activation energy for the uncatalyzed reaction?

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