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# Solving for Activation Energy from Variables

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Data:
T1 = 650
T2 = 700
K1 = 0.22 1/m.s
K2 = 1.3 1/m.s
Ea =
R = 8.315 kj/K.mol

I am using equation

ln k2 - ln k1 = Ln k2/k1 = Ea /R [1/T2 - 1/T1]

Since K1 + K2 are in 1/m.s do I have to get the inverse of those figures so that K1 = 4.545 m.s and K2 = .769 m.s?

Second, solving for Ea: Ea/8.315 kj/k.mol * [1/700-1/650]= How do I isolate so that I am solving for Ea?

##### Solution Summary

Let k1 and k2 be the rate constants determined at T1 and T2, respectively. Then you have two equations: ln k1 = lnA - Ea/(R T1) and ln k2 = lnA - Ea/(R T2). From these, you should be able to derive the necessary relationships (answer includes work and calculations).

##### Solution Preview

K1 and K2 are expressed in 1/ms only. So you don't have to take the inverse.

Let k1 and k2 be the rate constants determined at T1 and T2, respectively. Then you have ...

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