Explore BrainMass

Explore BrainMass

    Solving for Activation Energy from Variables

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    Data:
    T1 = 650
    T2 = 700
    K1 = 0.22 1/m.s
    K2 = 1.3 1/m.s
    Ea =
    R = 8.315 kj/K.mol

    I am using equation

    ln k2 - ln k1 = Ln k2/k1 = Ea /R [1/T2 - 1/T1]

    Since K1 + K2 are in 1/m.s do I have to get the inverse of those figures so that K1 = 4.545 m.s and K2 = .769 m.s?

    Second, solving for Ea: Ea/8.315 kj/k.mol * [1/700-1/650]= How do I isolate so that I am solving for Ea?

    © BrainMass Inc. brainmass.com March 4, 2021, 5:52 pm ad1c9bdddf
    https://brainmass.com/chemistry/chemical-kinetics/solving-activation-energy-variables-15055

    Solution Preview

    K1 and K2 are expressed in 1/ms only. So you don't have to take the inverse.

    Let k1 and k2 be the rate constants determined at T1 and T2, respectively. Then you have ...

    Solution Summary

    Let k1 and k2 be the rate constants determined at T1 and T2, respectively. Then you have two equations: ln k1 = lnA - Ea/(R T1) and ln k2 = lnA - Ea/(R T2). From these, you should be able to derive the necessary relationships (answer includes work and calculations).

    $2.19

    ADVERTISEMENT