T1 = 650
T2 = 700
K1 = 0.22 1/m.s
K2 = 1.3 1/m.s
R = 8.315 kj/K.mol
I am using equation
ln k2 - ln k1 = Ln k2/k1 = Ea /R [1/T2 - 1/T1]
Since K1 + K2 are in 1/m.s do I have to get the inverse of those figures so that K1 = 4.545 m.s and K2 = .769 m.s?
Second, solving for Ea: Ea/8.315 kj/k.mol * [1/700-1/650]= How do I isolate so that I am solving for Ea?© BrainMass Inc. brainmass.com September 19, 2018, 8:45 am ad1c9bdddf - https://brainmass.com/chemistry/chemical-kinetics/solving-activation-energy-variables-15055
K1 and K2 are expressed in 1/ms only. So you don't have to take the inverse.
Let k1 and k2 be the rate constants determined at T1 and T2, respectively. Then you have ...
Let k1 and k2 be the rate constants determined at T1 and T2, respectively. Then you have two equations: ln k1 = lnA - Ea/(R T1) and ln k2 = lnA - Ea/(R T2). From these, you should be able to derive the necessary relationships (answer includes work and calculations).