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    equilibrium constant Ke

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    Find the value of Ke for the reaction,

    A(g) + 2B (g) ---> 2C(g) + D(g)

    In which it was found that at equilibrium, [A] = 0.200 mol/L, [B] = 0.200 mol/L, [C] = 0.0500 mol/L, and [D] = 0.0750 mol/L.

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    Solution Summary

    This solution helps demonstrate how to calculate the equilibrium constant Ke of the reaction.