Explore BrainMass
Share

Explore BrainMass

    Ke for Equilibrium Concentrations

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    1, Calculate Ke for the following (equilibrium concentrations given below substances)

    a) H2 (g) + Br2 (g) ↔ 2 HBr (g) + heat
    [0.513] [0.62] [0.346]
    Ke = (0.346)^2/(0.513)(0.62) = 0.376

    b) N2O4 (g) + heat ↔ 2 NO2 (g)
    [0.0325] [0.022]

    Ke = [NO2]^2/[N2O4] = (0.022)^2/0.0325 = 0.149

    c) NH4SH (g) ↔ NH3 (g) + H2S (g) + heat
    [0.027] [0.0234] [0.209]
    Ke = [NH3][H2S]/[NH4SH] = (0.0234)(0.209)/(0.027) = 0.181

    2. For all three of the equilibria in problem #1 predict (1) how Ke is affected by an decrease in temperature, (2) predict how the equilibrium will shift when pressure is increased, (3) predict how the equilibrium will shift when the concentration of the underlined substance is increased, and (4) predict how the equilibrium will shift when the temperature is increased.

    © BrainMass Inc. brainmass.com October 10, 2019, 12:35 am ad1c9bdddf
    https://brainmass.com/chemistry/energetics-and-thermodynamics/ke-equilibrium-concentrations-297456

    Attachments

    Solution Preview

    1, Calculate Ke for the following (equilibrium concentrations given below substances)

    a) H2 (g) + Br2 (g) ↔ 2 HBr (g) + heat
    [0.513] [0.62] [0.346]
    Ke = (0.346)^2/(0.513)(0.62) = 0.376

    b) N2O4 (g) + heat ↔ 2 NO2 (g)
    [0.0325] [0.022]

    Ke = [NO2]^2/[N2O4] = (0.022)^2/0.0325 = 0.149

    c) NH4SH (g) ↔ NH3 (g) + H2S (g) + heat
    [0.027] [0.0234] [0.209]
    Ke = [NH3][H2S]/[NH4SH] = (0.0234)(0.209)/(0.027) = 0.181

    2. For all three of the equilibria in problem #1 predict (1) how Ke is affected by an decrease in temperature, (2) predict how ...

    Solution Summary

    The expert calculates Ke for equilibrium concentrations.

    $2.19