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# Ke for Equilibrium Concentrations

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1, Calculate Ke for the following (equilibrium concentrations given below substances)

a) H2 (g) + Br2 (g) ↔ 2 HBr (g) + heat
[0.513] [0.62] [0.346]
Ke = (0.346)^2/(0.513)(0.62) = 0.376

b) N2O4 (g) + heat ↔ 2 NO2 (g)
[0.0325] [0.022]

Ke = [NO2]^2/[N2O4] = (0.022)^2/0.0325 = 0.149

c) NH4SH (g) ↔ NH3 (g) + H2S (g) + heat
[0.027] [0.0234] [0.209]
Ke = [NH3][H2S]/[NH4SH] = (0.0234)(0.209)/(0.027) = 0.181

2. For all three of the equilibria in problem #1 predict (1) how Ke is affected by an decrease in temperature, (2) predict how the equilibrium will shift when pressure is increased, (3) predict how the equilibrium will shift when the concentration of the underlined substance is increased, and (4) predict how the equilibrium will shift when the temperature is increased.

https://brainmass.com/chemistry/energetics-and-thermodynamics/ke-equilibrium-concentrations-297456

#### Solution Preview

1, Calculate Ke for the following (equilibrium concentrations given below substances)

a) H2 (g) + Br2 (g) ↔ 2 HBr (g) + heat
[0.513] [0.62] [0.346]
Ke = (0.346)^2/(0.513)(0.62) = 0.376

b) N2O4 (g) + heat ↔ 2 NO2 (g)
[0.0325] [0.022]

Ke = [NO2]^2/[N2O4] = (0.022)^2/0.0325 = 0.149

c) NH4SH (g) ↔ NH3 (g) + H2S (g) + heat
[0.027] [0.0234] [0.209]
Ke = [NH3][H2S]/[NH4SH] = (0.0234)(0.209)/(0.027) = 0.181

2. For all three of the equilibria in problem #1 predict (1) how Ke is affected by an decrease in temperature, (2) predict how ...

#### Solution Summary

The expert calculates Ke for equilibrium concentrations.

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