For the chemical system shown below, it was found that [N2] = [O2] = 0.70 mol/L and [NO] = 0.22 mol/L, at equilibrium. Suppose that enough N2 was added to increase its concentration temporarily to 1.00 mol/L. When the system reaches equilibrium, what will be the new equilibrium concentrations of N2, O2, and NO?
N2(g) + O2(g) ? 2NO(g).
First, find K
K = [NO]^2/ [N2][O2] = (0.22)^2 / (0.70 x 0.70) = 0.0988
After reaching the new ...
The solution discusses equilibrium concentrations in a system.