How to calculate spring constant force
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If an object with a mass of xkg on the end of a spring with a mass of ykg, is pulled 0.2 m away from equilibrium on a horizontal table and released where it achieves a max velocity of Zm/s at X=0, how do you calculate the spring constant?
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Solution (a)
Because the object with mass x kg is pulled 0.2 m away from equilibrium, there is a restoring force. The energy that stores in the spring is PE = ½ kx2
At x = 0, there is no restoring force. All the potential energy in the spring is converted to kinetic energy:
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