The flat circular disc rotates about a vertical axis through O with a constant angular velocity of 240rpm. Prior to rotation, each of the 0.5kg sliding blocks has the position x=25mm with no force in its attached spring. Each spring has a stiffness of 400N/m. Neglect any friction between the blocks and the slots, and neglect the mass of the springs.
(a) Determine the value of x for each spring.
(b) Calculate the normal force N exerted by the side of the slot on the block.
Please refer to the attachment.
a) As the circular disc rotates, the blocks also rotate with the same speed viz. 240 rpm and each block experiences a centrifugal force F = mv2/r where m = mass of the block, v = tangential speed of the block, r = radial distance of the block from centre of the disc. This force F can be resolved into components as shown in the fig.. Fsinθ ...
The expert calculates the normal force exerted. The value of x for each spring is determined.
Normal force of chair
A chair of mass 13.0 kg is sitting on the horizontal floor; the floor is not frictionless. You push on the chair with a force = 38.0 N that is directed at an angle of 43.0 degrees below the horizontal and the chair slides along the floor.
Use Newton's laws to calculate the normal force that the floor exerts on the chair.View Full Posting Details