I have the following data:
Kw = 5.47x10 -14th
temperature = 50 degrees celcius
[H3O+] = x
pH = x
How do I find the value for [H3O+] and how do I find the value for pH?
We know that
Kw = [H3O+] * [OH-] = 5.47 * 10^-14
From standard tables, you can see that this value of Kw is for water at 50 degrees (go to this web page for a good discussion ...
The solution is given with a short explanation.