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Solving for Kw

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I have the following data:

Kw = 5.47x10 -14th
temperature = 50 degrees celcius
[H3O+] = x
pH = x

How do I find the value for [H3O+] and how do I find the value for pH?

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Solution Summary

The solution is given with a short explanation The expert solves for Kw.

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We know that

Kw = [H3O+] * [OH-] = 5.47 * 10^-14

From standard tables, you can see that this value of Kw is for water at 50 degrees (go to this web page for a good discussion ...

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