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    Solving for Kw

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    I have the following data:

    Kw = 5.47x10 -14th
    temperature = 50 degrees celcius
    [H3O+] = x
    pH = x

    How do I find the value for [H3O+] and how do I find the value for pH?

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    https://brainmass.com/chemistry/acids-and-bases/solving-kw-16171

    Solution Preview

    We know that

    Kw = [H3O+] * [OH-] = 5.47 * 10^-14

    From standard tables, you can see that this value of Kw is for water at 50 degrees (go to this web page for a good discussion ...

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