Oxalic acid H2C2O4 is a diprotic acid. Calculate the mass of acid in a solid given that a 0.7984 g sample of that solid required 45.00 mL of 0.300 M NaOH for neutralization.© BrainMass Inc. brainmass.com December 24, 2021, 7:34 pm ad1c9bdddf
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oxalic acid H2C2O4 is a diprotic acid. calculate the mass of acid in a solid given that a 0.7984 g sample of that solid required 45.00 mL of 0.300 M NaOH for neutralization.
1 mol of H2C2O4 can provide 2 moles of H+ in the neutralization since it is a diprotic acid.
For NaOH, 1 mole of NaOH only provide 1 mol of OH-.
H+ + OH- H2O
In the above reaction, 1 mole of H+ reacts with 1mol of OH .
Therefore, in the neutralization, 1 mol of H2C2O4 will react with 2 mol of NaOH.
That is, the moles of NaOH is twice that of H2C2O4 in the reaction.
The moles of NaOH used is
(45.00 mL) * (0.300 M) = (0.0450 L) * (0.300 M) = 0.0135 mol.
Then it requires (0.0135 mol) / 2 = 0.00675 mol of H2C2O4 in neutralization.
The molar mass of H2C2O4 is 2 *1 + 2* 12 + 4* 16 = 90 g/mol
So the mass of 0.00675 mol of H2C2O4 is
(90 g/mol) * (0.00675 mol) = 0.6075 grams.
There are 0.6075 g of oxalic acid in the solid.© BrainMass Inc. brainmass.com December 24, 2021, 7:34 pm ad1c9bdddf>