Purchase Solution

titration of benzoic acid with NaOH

Not what you're looking for?

Ask Custom Question

C6H5COOH ( benzoic acid ) = C6H5COO- (aq) + H+ (aq) Ka = 6.46 x 10^-5
Benzoic acid dissociates in water as shown in the equation above. A 25.0 ml sample of an aqueous solution of pure benzoic acid is titrated using standardized 0.150 M NaOH

A) After addition of 15.0ml of the 0.150 M NaOH , the pH of the resulting solution is 4.37. Calculate each of the following
I) [H+] in the solution

Ii) [OH-] in the solution

Iii) The number of moles of NaOH added

Iv) The number of moles of C6H5COO- (aq) in the solution

V) The number of moles of C6H5COOH in the solution

B) State whether the solution at the equivalence point of the titration is acidic , basic or neutral. Explain your reasoning
In a different titration , a 0.7529 g sample of a mixture of solid. C6H5COOH and solid NaCL is dissolved in water and titrated with 0.150 M NaOH. The equivalence point is reached when 24.78ml of the base solution is added.

C) calculate each of the following
(I) The mass, in grams, of benzoic acid in the sample
(Ii) The mass percentage of benzoic acid in solid sample

Purchase this Solution
Solution Summary

It investigates the titration process of benzoic acid with NaOH. The solution is detailed and well presented.

Purchase this Solution
Free BrainMass Quizzes
General Chemistry - Classification of Matter

This test will assess your knowledge on the classification of matter which includes elements, compounds and mixtures.

Functional groups in Organic Chemistry

You will be tested on the names of functional groups in Organic Chemistry. It is very important to know the functional groups to understand Organic reactions.

Match Elements with their Symbols

Elements are provided: choose the matching one- or two-letter symbol for each element.

Organic Chemistry Naming: Alkanes

This is a quiz which is designed to assist students with learning the nomenclature used to identify organic compounds. This quiz focuses on the organic compounds called Alkanes.

Thermochemistry

The quiz helps in revising basic concepts about thermochemistry.

View More Free Quizzes
Related BrainMass Solutions

  • Acetic Acid Lab

    Procedure 1: NaOH titrated with benzoic acid 1. Moles of benzoic acid: 2.

  • Extraction of benzoic acid, pre lab questions

    This means that benzoic acid will be present in top layer. 3. Since on mixing with NaOH, benzoic acid forms sodium benzoate which is more soluble in water, therefore, benzoic acid will be in 3M NaOH layer.

  • Titrating hydrochloric and acetic acids with NaOH

    See attachment for titration details. Titration 2: 5.00mL unknown concentration of acetic acid with 20.00 mL of H2O added and 2 drops of phenolpthalein to show end-point. 1.0M NaOH What is the molarity of the acetic acid?

  • Solubility of organic compounds

    In this case also, NaOH is polar but the solution is basic, I means Na salts of benzoic acid is soluble but instead Chloride salt given of aniline (last one) is soluble.

  • Titration Conduction

    Vinegar is called acetic acid and has the formula CH3COOH RXN equation: CH3COOH + NaOH --> CH3COO- + H2O + Na+ When ou do a titration, especially with monoprotic (only one acidic proton) acids, the moles of acid will equal the moles of base

  • Equivalence volume of the second titration

    When titrating a monoprotic acid, such as HCl, with sodium hydroxide (NaOH), the molar ratio for the reaction is 1:1 - that is, one mole of NaOH will neutralize one mole of HCl - and all of the following are true at the equivalence point: (a) Moles

  • Titration of 50 mL 0.108 M propanoic acid (HPr) with 0.150 M NaOH

    6634 Titration of 50 mL 0.108 M propanoic acid (HPr) with 0.150 M NaOH A sample of 0.0054 mol propanoic acid was dissolved in water to give 50ml solution. This solution is titrated with 0.150 M of NaOH.

  • Titration Curve of Weak Acid with Strong Base

    245959 Titration Curve of a Weak Acid with a Strong Base A 30 mL sample of 0.35 M of lactic acid is titrated with a 0.25 M NaOH solution. Calculate the pH before NaOH is added. After 20 mL of NaOH is added. After 42 mL. After 45 mL. After 60 mL.

  • Concentration through Titration

    Titrated with 12.2mL of standardized hydrochloric acid) b) From the titration with NaOH  the reaction for the titration of sodium tetraborate with hydrochloric acid solution is: Na2B4O7(aq) + 2HCl(aq) + 5H2O(l)  4H3BO3(aq) + 2NaCl(aq) (To the solution

View More Related Solutions