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    Titration Conduction

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    A titration was conducted to determine the percent of acetic acid within vinegar. The reaction of this titration is HC(2)H(3)O(2) --->NaC(2)H(3)O(2) +H(2)O (water)

    Given Concentration of NaOH 0.2959 M.

    Final Buret Reading:26.72 mL

    Initial buret reading :0.02 mL

    Volume of NaOH added: 26.70 mL

    determine: Mass of acetic acid and percent acetic acid

    Edit: assume density of vinegar to be 1.008 g/mL.60 mL of vinegar was obtained

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    https://brainmass.com/chemistry/acids-and-bases/titration-conduction-56675

    Solution Preview

    Your reaction equation is not complete...
    Vinegar is called acetic acid and has the formula CH3COOH

    RXN equation:

    CH3COOH + NaOH --> CH3COO- + H2O + Na+

    When ou do a titration, especially with monoprotic (only one acidic proton) acids, the moles of acid will equal the moles ...

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