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# Titration Conduction

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A titration was conducted to determine the percent of acetic acid within vinegar. The reaction of this titration is HC(2)H(3)O(2) --->NaC(2)H(3)O(2) +H(2)O (water)

Given Concentration of NaOH 0.2959 M.

Final Buret Reading:26.72 mL

Initial buret reading :0.02 mL

Volume of NaOH added: 26.70 mL

determine: Mass of acetic acid and percent acetic acid

Edit: assume density of vinegar to be 1.008 g/mL.60 mL of vinegar was obtained

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#### Solution Preview

Your reaction equation is not complete...
Vinegar is called acetic acid and has the formula CH3COOH

RXN equation:

CH3COOH + NaOH --> CH3COO- + H2O + Na+

When ou do a titration, especially with monoprotic (only one acidic proton) acids, the moles of acid will equal the moles ...

#### Solution Summary

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