A titration was conducted to determine the percent of acetic acid within vinegar. The reaction of this titration is HC(2)H(3)O(2) --->NaC(2)H(3)O(2) +H(2)O (water)
Given Concentration of NaOH 0.2959 M.
Final Buret Reading:26.72 mL
Initial buret reading :0.02 mL
Volume of NaOH added: 26.70 mL
determine: Mass of acetic acid and percent acetic acid
Edit: assume density of vinegar to be 1.008 g/mL.60 mL of vinegar was obtained© BrainMass Inc. brainmass.com March 4, 2021, 6:41 pm ad1c9bdddf
Your reaction equation is not complete...
Vinegar is called acetic acid and has the formula CH3COOH
CH3COOH + NaOH --> CH3COO- + H2O + Na+
When ou do a titration, especially with monoprotic (only one acidic proton) acids, the moles of acid will equal the moles ...
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