frequency of the dominant allele (p) in the population

Related BrainMass Solutions

• Hardy Weinberg Problems

  The p is the frequency of the dominant alleles in a population while the q is the frequency of recessive allele in the population. The sum of these two percentages will always add up to 100% which is why p +q = 1.

• calculate the genotype frequencies

  Now that you know the frequency of q in the population you can determine the frequency of p by using the second equation p+q = 1. Now we have p+0.45 = 1 so p = 0.55. Once you have the frequencies of p and q these are your allele frequencies.

• Hardy-Weinberg Equilibrium for Populations

  What are the frequencies of webbed feet and non-webbed feet traits in this population? ii) How is the dominant allele frequency calculated from this population?

• Calculation of dominant and recessive alleles in population

  q2 = .0001 or q = 0.01 While putting value of q in above equation we get p2 + 0.02 p + 0.0001 = 1 or, p2 + 0.02 p -0.9999 = 0 or, p = 0.99 Therefore frequency of dominant and recessive allele is 0.99 and 0.01 respectively Carriers are heterozygote

• Genetics and Hardy-Weinberg equation

  Based upon the Hardy Weinberg formula, how many individuals in this population would be expected to have white flowers? In the Hardy-Weinberg formula, p(squared) is the frequency of the dominant allele, in this case 0.056 (8/144).

• Hardy-Weinberg Problem

  Lets make the B allele=p and G allele=q: Frequency of BB genotype = p^2 Frequency of BG genotype = 2pq Frequency of GG genotype = q^2 So according to the information given in the question we know this: 420 plants of type BB(

• Hardy Weinberg Explains Evolution With Mathematics

  The mathematical equation known as the Hardy-Weinberg equation is: p² + 2pq + q² = 1 Where: p=frequency of the dominant allele for a given trait q=requency of the recessive allele for a given trait So: p^2 is the frequency for homozygous dominant

• Genetic frequency

  Newfie moose have a frequency of 0.72 for the same allele.

• A Hardy Weinberg carnation problem

  If the allele frequency for R is 0.23, how many pink individuals would you expect in a population of 2500, if you assume the population is in Hardy-Weinberg equilibruim. Help is given.