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    Hardy-Weinberg Equilibrium for Populations

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    A) Address the following Hardy-Weinberg Equilibrium problem.

    i) A population of iguanas on the Galapagos Islands has 20 individuals with webbed feet and 180 individuals with the dominant trait of non-webbed feet. What are the frequencies of webbed feet and non-webbed feet traits in this population?

    ii) How is the dominant allele frequency calculated from this population?

    iii) Calculate the genotype frequencies: p2 -the frequency of the dominant homozygotes; 2pq -the frequency of heterozygotes; and q2 -the frequency of the recessive homozygotes (hint: insert the values calculated for p and q such that p2+2pq+q2=1.0). Explain why p2 and q2 represent the proportion of dominant and recessive homozygotes, respectively, and why 2pq represents the proportion of heterozygotes (hint: consider the law of independent assortment and the laws of probability).

    iv) Is the population in Hardy-Weinberg Equilibrium? Why or why not?

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    https://brainmass.com/biology/genetics/hardy-weinberg-equilibrium-populations-109925

    Solution Preview

    Please see the attached file.

    Webbed feet (recessive) = 20 (ww)
    Non-webbed feet (dominant) = 180 (WW + Ww)
    Total population = 180 + 20 = 200

    Frequency of webbed feet = 20/200 = 0.1
    q² = 0.1
    q = √0.1 = 0.316
    p + q = 1
    p = 1- q = 1 - 0.316 = 0.684
    p² = 0.684² = 0.468
    2pq = 2(0.684)(0.316) = 0.432

    Now going back to answer the questions:-

    i) Frequency of webbed feet (q²) = 0.1
    Frequency of non-webbed feet (p² + ...

    Solution Summary

    The expert examines Hardy-Weinberg Equilibrium for populations.

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