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The weights of items produced by a company are normally distributed with a mean of 4.5 ounces and a standard deviation of 0.3 ounces.

a. What is the probability that a randomly selected item from the production will weigh at least 4.14 ounces?

Look at attachement too!!!
I think I did this all wrong can you help me out? IF I did do it all wrong can you please correct and explain? If you can't see the greater than or equal to symbols please look at attachment.
P(x 4.14)
z = 4.14 - 4.5 / .3 = -1.2

P(x 4.14) =
Or
P (0 < z < 1.2) = 0.3849
Using the symmetric property of the z-curve, we have P(-1.5 < z < 0) = 0.3849 too.
And P(z < -1.2) = P (z > 1.2)
So
P(z < -1.5) + P(-1.5 < z < 0) + P (0 < z < 1.5) + P (z > 1.5) = 1
P(z < -1.5) + 0.3849 + 0.3849 + P(z < -1.5) =1
P(z < -1.5) = 0.1151

1 - .1151 = .8849 or 88.49%

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Solution Summary

The solution finds the probability of the weight of products, which is normally distributed.

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