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# Anova and confidence intervals

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Using the confidence intervals: 95%
Determine which groups differ in average shelf life.
A B C D
94 88 76 82
100 89 69 80
90 88 76 82
97 83 79 78
101 79 80 89
90 82 72 80
give test statistic, hypothesis, decision rule and hypothesis

https://brainmass.com/statistics/analysis-of-variance/anova-confidence-intervals-9762

#### Solution Preview

Null Hypothesis:
Ho: mu1 - mu2 = 0
Alternative hypothesis:
H1: mu1 - mu2 != 0

Mean calculations:
<A> = sum(A)/6 = 572/6 =95.33
<b> = 509/6 = 84.83
<C> = 452/6 = 75.33
<D> = 491/6 = 81.83
sum((A-<A>)^2) = 115.33
sum((B-<b>)^2) = 82.83
sum((C-<C>)^2) = 87.83
sum((D-<D>)^2) = 72.57

If t(calculated) > t(table) => Ho rejected

for any combination: (like A and B)
sqrt((1/n1) + ...

#### Solution Summary

The expert examines an ANOVA and confidence interval. The average shelf life of different groups are given. The solution answers the question(s) below.

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