The following data were collected from a repeated-measures study. Use an ANOVA with an alpha = .05 to evaluate the mean difference between treatments.
Treatment
A B
2 6
2 6 G = 28
4 4 (sum of X-squared) åX2 = 128
0 4
T = 8 T = 20
SS = 8 SS = 4
Multiple choice
a) F(1,6) = 9.00, with a critical value of 5.99. Fail to reject H0 and conclude that the mean difference between treatments is not significant.
b) F(1,7) = 9.00, with a critical value of 5.59. Fail to reject H0 and conclude that the mean difference between treatments is not significant.
c) F(1,7) = 10.13, with a critical value of 9.00. Reject H0 and conclude that the mean difference between treatments is significant.
d) F(1,3) = 9.00, with a critical value of 10.13. Fail to reject H0 and conclude that the mean difference between treatments is not significant.
Solution Summary
ANOVA is applied to find the mean difference between two types of treatments.
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