200 grams of boiling water and 100 grams of ice-cold liquid water are combined in a sealed thermos bottle.
(b) What is the change in entropy for the parts (hot water and cold water) of the system, and for the system as a whole?
Hints: HF = 333.55 J/K, C = 4.19J/g
(a)What is the maximum possible efficiency of a steam engine operating between the temperatures of freezing water (0C) and burning books (451F ~ 233C)?
(b)What is the maximum possible efficiency of a steam engine operating between the temperatures of boiling water (100C) and burning books (451F ~ 233C)?
(c) Which operating range is more efficient? Why?
Hint: 273K= 0C
This solution is comprised of detailed step-by-step calculations and explanation of the given problems. The solution also provides students with a clear perspective of the underlying concepts.
Physics: Second Law of Thermodynamics
1. Use the second law of thermodynamics to explain why many poor people in developing countries live on a mostly vegetarian diet?
2. Someone wants you to invest money in an automobile engine that will produce more energy than the energy in the fuel (such as gasoline or electricity) used to run the motor. What is your response? Hint: Second law of thermodynamics.View Full Posting Details