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    Variation of Range Projection with Angle of Projection

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    Range of a particle when launched at an angle of 15 degree with the horizontal is 1.5 km. What is the range of the projectile when launched at an angle of 45 degree with the horizontal. (assume, g = 10 m/s^2)

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    Solution Preview

    Range of projectile, is given as:

    R = u^2 * sin (2A)/g

    where u is magnitude of initial velocity (velocity of ...

    Solution Summary

    The expert examines the variation of range projection with angle of protection.