A projectile is fired in such a way that its horizontal range is equal to three times its maximum height. What is the angle of projection?
Please see the attachment to see how you can resolve velocity vector in to components.
<br>The horizontal range is determined by the horizontal component of the velocity which is Vx and the maximum height is determined by the y component of the velocity Vy
<br>Vx = V Cos(A) ...
The problem is solved giving all necessary mathematical steps. It will enable you to do similar problems yourself.