Purchase Solution

Electrostatics: Unequal Charge density on parallel plates

Not what you're looking for?

Ask Custom Question

(See attached file for full problem description)

---
1. Consider two infinite parallel plane conducting plates, of finite thickness, with separation d. Suppose a charge density of sigma; is placed on one plate, while the other plate has -2sigma.
A) Determine the resulting charge densities on each of the 4 surfaces
B) Determine the electric field between and outside the plates

Use superposition of Gaussian surfaces.

Attachments
Purchase this Solution
Solution Summary

The unequal and opposite charges are given to the plates parallel to each other, the field is calculated everywhere.

Purchase this Solution
Free BrainMass Quizzes
Variables in Science Experiments

How well do you understand variables? Test your knowledge of independent (manipulated), dependent (responding), and controlled variables with this 10 question quiz.

The Moon

Test your knowledge of moon phases and movement.

Basic Physics

This quiz will test your knowledge about basic Physics.

Classical Mechanics

This quiz is designed to test and improve your knowledge on Classical Mechanics.

Intro to the Physics Waves

Some short-answer questions involving the basic vocabulary of string, sound, and water waves.

View More Free Quizzes
Related BrainMass Solutions

  • Electrostatics

    413722 Physics: 5 Problems on electrostatics. 4a. Consider the parallel plate capacitor, where the surface charge density is 0.02 uC/m^2, and the distance between the plate is 0.01m. What is the potential difference between the two plates? 4b.

  • Two problems on electrostatics

    147202 Two problems on electrostatics 1. Two charged concentric spherical shells have radii 10.0cm and 15.0cm. The charge on the inner shell is 4.00X10^-8C, and that on the outer shell is 2.00X10^-8C.

  • Electrostatics and Oscillations: Oscillations in a capacitor

    282251 Electrostatics and Oscillations: Oscillations in a Capacitor A square parallel plate capacitor with vertical plates of area A and distance d, charged with a constant charge Q and is completely filled with a dielectric material the same dimension

  • Working with parallel plate capacitor - charge density

    9329 Working with parallel plate capacitor - charge density According to section E3.4, the electric field E between two parallel plates with opposite, uniformly distributed charges is ( as long as the plates are very large compared to their seperation

  • Capacitors: Types, Expressions, Effect of Insertion

    Let the charge density on each plate be σ c/m2 (on one plate +ve and on the other -ve) and potential difference between the plates V. +σ c/m2 Area A Pot. Diff.

  • Capacitors and Parallel Conducting Plates

    The plates are so large compared to their separation that the electric field between them can be considered to depend only on z. Between the plates there is a free charge density where K is a constant.

  • Capacitance: What is the distance between the plates?

    8961 Capacitance: What is the distance between the plates? When a potential difference of 178 V is applied to the plates of a parallel-plate capacitor, the plates carry a surface charge density of 47nC/cm^2.

  • Capacitor - with and without dielectric

    Compute the capacitance, charge, charge density, field strength in the space between the plates and also the energy stored in the capacitor.

  • A parallel plate capacitor with plates of area A and plate

    The electric field between two large parallel plates is given by: σ = charge density and ε = permittivity Since there are two dielectric materials, we can split the electric field into two and the total will be calculated as: Note that

View More Related Solutions