Capacitance: What is the distance between the plates?

When a potential difference of 178 V is applied to the plates of a parallel-plate capacitor, the plates carry a surface chargedensity of 47nC/cm^2.

What is the distance between the plates? Answer in units of micrometers.

Solution Preview

The Capacitance(C) of a parallel plate capacitor is given by :

C = (e0 * A )/d .....(i) (This is in MKS or SI units)

Where:
e0=epsilon=permittivity of free space =8.854*10^-12 Farad/m.
A= Area of the plates (in m^2 i.e. square meters)
d= separation between the plates (in meters)

We also know that Capacitance is defined as :

C=Q/V ....(ii)
where :
C=capacitance(in Farad, F)
Q=charge developed ...

Solution Summary

The solution explains the problem and shows the calculations to arrive at the answer.

1. What is the net capacitance of a capacitor given:
Relative permitivity is 500
The area is one square meter
Thedistancebetweenthe plates is 0.001 meters

The problem states:
You have two flat metal plates, each of area 1.00 m^2, with which to construct a parallel-plate capacitor.
(a) If the capacitor of the device is to be 1.00 F, what must be the separation betweentheplates?
(b) Could this capacitor actually be constructed?
Please review my solution below and correct

Calculate the capacitance of a spherical shell capacitor given two plates one charged at +Q coulombs at a radius (a) from the center another plate charges at -Q coulombs at a radius (b) from the center and given that:
The voltage at a region between the spherical shells is given by
V(r) = kQ/r (a >

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