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    Capacitance: What is the distance between the plates?

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    When a potential difference of 178 V is applied to the plates of a parallel-plate capacitor, the plates carry a surface charge density of 47nC/cm^2.

    What is the distance between the plates? Answer in units of micrometers.

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    Solution Preview

    The Capacitance(C) of a parallel plate capacitor is given by :

    C = (e0 * A )/d .....(i) (This is in MKS or SI units)

    e0=epsilon=permittivity of free space =8.854*10^-12 Farad/m.
    A= Area of the plates (in m^2 i.e. square meters)
    d= separation between the plates (in meters)

    We also know that Capacitance is defined as :

    C=Q/V ....(ii)
    where :
    C=capacitance(in Farad, F)
    Q=charge developed ...

    Solution Summary

    The solution explains the problem and shows the calculations to arrive at the answer.