When a potential difference of 178 V is applied to the plates of a parallel-plate capacitor, the plates carry a surface charge density of 47nC/cm^2.
What is the distance between the plates? Answer in units of micrometers.© BrainMass Inc. brainmass.com March 4, 2021, 5:44 pm ad1c9bdddf
The Capacitance(C) of a parallel plate capacitor is given by :
C = (e0 * A )/d .....(i) (This is in MKS or SI units)
e0=epsilon=permittivity of free space =8.854*10^-12 Farad/m.
A= Area of the plates (in m^2 i.e. square meters)
d= separation between the plates (in meters)
We also know that Capacitance is defined as :
C=capacitance(in Farad, F)
Q=charge developed ...
The solution explains the problem and shows the calculations to arrive at the answer.