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    Parallel Plate Capacitor Charge

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    A 100-uF parallel-plate capacitor is charged to 500 V. It is then disconnected from the charging source and insulated. (a) How much energy is stored on the capacitor? (b) If the plates are pulled apart to a seperation that is twice their initial separation, what energy is stored on the capacitor? (c) If the answers are not identical, account for their difference.

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    Solution Preview

    (a) The energy stored in a capacitor is given by the equation,

    U = 1/2 CV2 = 1/2 (100)*(500)2 = 1.25 x 107 Coulomb

    (b) In part (a) Capacitance C = KEA / d
    d ~ Capacitor plate separation ...

    Solution Summary

    This solution includes calculations and explanation. 145 words.