See the attached file.
1. In a radical system the electric potential is given by the function
V(r)=k(1/r2 - 1/r)
Where k is constant and r is the radical distance.
a. Find the electric field as a function of distance.
b. If a positive charge was released in this system, at what radius would it be at equilibrium (i.e. if electric potential was height and you rolled a ball on this landscape would it come to a rest?)
Take the derivative and put it equal to zero.
2. The earth has an electric field of 150N/C which arises because the separation of charge between the Earth's surface and the ionsphere which is 100 km above the surface of the earth. Assuming the Earth's atmosphere can be considered to be similar to a parallel plate capacitor (whose area is the area of the planet) what is the charge stored in this capacitor?
Treat the planet's atmosphere like a parallel plate capacitor. Use the parallel-plate capacitor equations.© BrainMass Inc. brainmass.com October 25, 2018, 8:52 am ad1c9bdddf
See the attached files.
The solution is attached below in two files. the files are identical in content, only differ in format. The first is in MS Word format, while the other is in Adobe pdf format. Therefore you can choose the format that is most ...
The solution discusses the electric fields and positive charges.
Physics: Electric Field a the Mid-Point of Two Charges
The electric field midway between two equal but opposite point charges is 1870 N/C, and the distance between the charges is 19.2 cm. What is the magnitude of the charge on each?
-Please show all steps including numerical solution.View Full Posting Details