# Calculate the magnitude of the electric field with distribution of charges

A. Calculate the magnitude of the electric field at the origin due to the following distribution of charges: +q at (x,y) = (a,a), +q at (a,-a), -q at (-a,-a) and -q at (-a,a). Where q = 2.25*10^-7C and a = 8.85 cm.

B. (view image attached) Set up an 8-point compass at the origin, where north points along the positive y-axis, such as that shown in the diagram to the right. What is the direction of the electric field at the origin created by the charge distribution given in the previous part? (for example, 'N', 'NE', etc., or if no net field enter 'NIL'.

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A. Calculate the magnitude of the elctric field at the origin due to the following distribution of charges: +q at (x,y) = (a,a), +q at (a,-a), -q at (-a,-a) and -q at (-a,a). Where q = 2.25*10^-7C and a = 8.85 cm.

The magnitude of an electric field due to a single charge at the origin is:

The number ...

#### Solution Summary

With good explanations and calculations, the problems are solved.