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# Conductors and Dielectrics

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a. A piece of plexiglass (k = 3.2) is placed above an infinite plane of charge with charge density sigma = 0.1 uC/m^2. Compute the bound charge on the bottom surface of the dielectric. Be careful of the sign.

b. A material is charged such that the electric field just inside it is 10N/C and is pointed into the boundary. The electric field just outside the material is 18N/C and is pointed away from the boundary. Both fields are perpendicular to the boundary. What is the surface charge density?

##### Solution Summary

When a dielectric is placed in an electric field, bound polarization charges appear on the opposite surfaces. The origin of these polarization charges is the polarization of the molecules of the medium. The electric field due to the infinite plane sheet of charge can be found using E = sigma/2e0. For b, we use Gauss's law to determine the electric fields across a boundary.

##### Solution Preview

a) When a dielectric is placed in an electric field, bound polarization charges appear on the opposite surfaces. The origin of these polarization charges is the polarization of the molecules of the medium

Electric field due ...

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