A parallel plate capacitor with plates of area A and plate separation d has the region between the plates filled with two dielectric materials (ε1 and ε2) as shown in the figure. Determine the capacitance and show that when ε1= ε2= ε your result becomes the same as that for a capacitor containing a single dielectric:
See equation and diagram in the attached file.
Please see the attached file.
The electric field between two large parallel plates is given by:
σ = charge density and ε = permittivity
Since there are two dielectric ...
The solution provides full explanations on the concept of parallel plate capacitor and then step-by-step calculations.