Electric Field and Stored Energy of Parallel-Plate Capacitor

A parallel-plate capacitor with plate area of 2 m^2 and a separation of 1.0 mm is charged to 100 V.

(a) What is the electric field between the plates?
(b) what is the energy per unit volume in the space between the plates?
(c) find the total energy by multiplying your answer from part (b) by the total volume between the plates.
(d) find the capacitance of C.
(e) calculate the total energy from U=1/2CV^2, and compare your answer with the result from part (c).

Solution Preview

A parallel-plate capacitor with plate area of 2 m^2 and a separation od 1.0 mm is charged to 100 V.

(a) What is the electric field between the plates?

F = V/d = 100/0.001 = 10^5 V/m

(b) what is ...

Solution Summary

This is a step-by-step solution computing the capacitance, electric field, and energy stored in a parallel-plate capacitor. All calculations are included.

A parallel-platecapacitor is connected to a battery that maintains potential difference V between the plates. If the plates of the capacitor are pulled farther apart, do the following quantities increase, decrease, or remain the same?
(a) Electricfield between the plates;
(b) charge on the plates;
(c) capacitance;
(d)

An electron is released from rest at the negative plate of a parallel plate capacitor. The charge per unit area on each plate is phi= 1.8 x 10 ^-7 C/m^2, and the plates are separated by a distance of 1.5 x 10^-2 m.
How fast is the electron moving just before it reaches the positive plate?

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Find the capacitance.
It is connected to a 40 V battery.
(i) What is the charge on each plate?
(ii) What is the energystored in the capacitor?
Repeat the calculations for the same capacitor with the air gap re

Two parallel plates are .005m apart and are each 2m2 in area. The plates are in vacuum and an electric potential difference of 10,000V is applied across them.
1) Find the:
a)capacitance,
b)the charge on each plate
c)the electricfield intensity in the space between, and
d) the storedenergy.
2) If a dielectric mater

Imagine that you would like to design a parallel plate capacitor that could store 1 J of electrical energy in the electricfield between its plates when connected to a 1.5 V battery. Imagine that you can arrange things so that the plates can be separated by a distance d as small as 0.5 mm. (Hint argue that the electricfield st

Part 1
A parallel-platecapacitor has an area of 5.19 cm2, and the plates are separated by 1.06 mm with air between them. It stores a charge of 334 pC. What is the potential difference across the plates of the capacitor?
(in V)
Part 2
What is the magnitude of the uniform electricfield in the region between the plates

Part 1
Consider the Earth and a cloud layer 760 m above the Earth to be the plates of a parallel-platecapacitor. If the cloud layer has an area of 1.03 km2 = 1.03E+6 m2, what is the capacitance?
Part 2
If an electricfield strength greater than 4.29E+6 N/C causes the air to break down and conduct charge (lightning), w

A slab of copper of thickness b = 1.167 mm is thrust into a parallel plate capacitor of C = 2.00×10-11 F of gap d = 7.0 mm, as shown in the figure (image attached); it is centered exactly halfway between the plates. What is the capacitance after the slab is introduced?
If a charge q = 4.00×10-6 C is maintained on the plates,

See the attached file.
1. In a radical system the electric potential is given by the function
V(r)=k(1/r2 - 1/r)
Where k is constant and r is the radical distance.
a. Find the electricfield as a function of distance.
b. If a positive charge was released in this system, at what radius would it be at equilibrium (i.e