Electric Field and Stored Energy of Parallel-Plate Capacitor
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A parallel-plate capacitor with plate area of 2 m^2 and a separation of 1.0 mm is charged to 100 V.
(a) What is the electric field between the plates?
(b) what is the energy per unit volume in the space between the plates?
(c) find the total energy by multiplying your answer from part (b) by the total volume between the plates.
(d) find the capacitance of C.
(e) calculate the total energy from U=1/2CV^2, and compare your answer with the result from part (c).
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This is a step-by-step solution computing the capacitance, electric field, and energy stored in a parallel-plate capacitor. All calculations are included.
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A parallel-plate capacitor with plate area of 2 m^2 and a separation od 1.0 mm is charged to 100 V.
(a) What is the electric field between the plates?
F = V/d = 100/0.001 = 10^5 V/m
(b) what is ...
Purchase this Solution
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