Electric Field and Stored Energy of Parallel-Plate Capacitor

A parallel-plate capacitor with plate area of 2 m^2 and a separation of 1.0 mm is charged to 100 V.

(a) What is the electric field between the plates?
(b) what is the energy per unit volume in the space between the plates?
(c) find the total energy by multiplying your answer from part (b) by the total volume between the plates.
(d) find the capacitance of C.
(e) calculate the total energy from U=1/2CV^2, and compare your answer with the result from part (c).

Solution Preview

A parallel-plate capacitor with plate area of 2 m^2 and a separation od 1.0 mm is charged to 100 V.

(a) What is the electric field between the plates?

F = V/d = 100/0.001 = 10^5 V/m

(b) what is ...

Solution Summary

This is a step-by-step solution computing the capacitance, electric field, and energy stored in a parallel-plate capacitor. All calculations are included.

... E = dV/dr (electric field is the potential gradient ... is given by the sum of the energies stored in individual ... As we have seen above, energy stored in a parallel...

... 1) a)capacitance, Since we are dealing with parallel plate, which can be treated ... c)the electric field intensity in the space between, and. d) the stored energy. ...

... ion's electric potential energy as it moves from inside to outside the cell? A 3.0 3.0 parallel-plate capacitor has a 3.0 spacing. The electric field strength ...

... voltage across a capacitor is doubled, the amount of energy it can store: (a) doubles (b ... A tiny positive charge of 50.0 uC is in a nonuniform electric field. ...

... of energy by also computing the change in the energy stored in the field between the ... plate can be considered as being placed in the electric field of the ...

... By conservation of energy (the electric force is a conservative force), the loss of potential energy is equal ... an area where there is a magnetic field of 2T ...

... of questions pertaining to parallel plate capacitors are presented ... use Gauss relationship that the Electric field is equal ... the fact that the energy stored in ...

A parallel-plate capacitor is connected to a battery that maintains ... (a) Electric field between the ... on the plates; (c) capacitance; (d) energy stored in the ...

... What would be the change in potential energy of the electron ... the change in the Kinetic energy, and using ...Electric field intensity between the two plates of the ...

... shows how to calculate the capacitance and energy stored after a ... plates are +Q and Q, then the potential difference Q ... 0 A V0 Q And the electric field is E0 ...