Explore BrainMass

# Electric Field and Stored Energy of Parallel-Plate Capacitor

Not what you're looking for? Search our solutions OR ask your own Custom question.

This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

A parallel-plate capacitor with plate area of 2 m^2 and a separation of 1.0 mm is charged to 100 V.

(a) What is the electric field between the plates?
(b) what is the energy per unit volume in the space between the plates?
(c) find the total energy by multiplying your answer from part (b) by the total volume between the plates.
(d) find the capacitance of C.
(e) calculate the total energy from U=1/2CV^2, and compare your answer with the result from part (c).

https://brainmass.com/physics/electric-magnetic-fields/electric-field-and-stored-energy-of-parallel-plate-capacitor-118733

#### Solution Preview

A parallel-plate capacitor with plate area of 2 m^2 and a separation od 1.0 mm is charged to 100 V.

(a) What is the electric field between the plates?

F = V/d = 100/0.001 = 10^5 V/m

(b) what is ...

#### Solution Summary

This is a step-by-step solution computing the capacitance, electric field, and energy stored in a parallel-plate capacitor. All calculations are included.

\$2.49