A steam turbine takes in steam at the rate of 6000 kg hour^-1 and its power output is 800 kW. Neglect any heat loss from the turbine. Find the change in the specific enthalpy of the steam as it passes through the turbine if (a) the entrance and exit are at the same elevation and the entrance and exit velocities are negligible (b) the entrance velocity is 50 ms^-1 and the exit velocity is 200 ms^-1, with the outlet pipe being 2 m above the inlet. Please see the attached file.© BrainMass Inc. brainmass.com March 5, 2021, 12:40 am ad1c9bdddf
As the steam turbine is steady state system, we can use steady flow energy equation as,
m[h1 + (C1^2/2) + z1*g] - Q =m[h1 + (C1^2/2) + z1*g] + W ----------------(1)
Where, m is flow rate (kg/s), h1 and h2 are enthalpy of steam at inlet and outlet respectively, C1 and C2 are velocities of steam at inlet and outlet, Z1 and Z2 are height of inlet and outlet, Q is heat loss (negative sign because heat is released), W is work done by system (output power per kg per s) and g is gravitational acceleration.
A step by step explanation to calculate change in the specific enthalpy of the steam in steam turbine.