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Velocity of a proton accelerated by an electric field

A proton is accelerated from rest by an electric field. The electric field starting point's potential is zero but the ending point electrostatic potential is -5,000 volts. I need to determine how to find the velocity of the proton at the ending point of 9.78 x 10^5 meters/second.

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Let the distance between the start and end point be 'd'
Potential Difference V = 5000 V

Electric field, E = Potential difference / Separation = V/d

E = V/d ------------- (1)

Force ...

Solution Summary

Velocity of a proton that was accelerated by an electric field is found. I have provided every step of the solution so that the student can learn from it.