A proton is accelerated from rest by an electric field. The electric field starting point's potential is zero but the ending point electrostatic potential is -5,000 volts. I need to determine how to find the velocity of the proton at the ending point of 9.78 x 10^5 meters/second.
Let the distance between the start and end point be 'd'
Potential Difference V = 5000 V
Electric field, E = Potential difference / Separation = V/d
E = V/d ------------- (1)
Velocity of a proton that was accelerated by an electric field is found. I have provided every step of the solution so that the student can learn from it.