A proton enters a region where the electric field has a magnitude of 500 N/C and is produced by two charged plates. The length of the plates is .200M. The initial velocity is 3X10^6 m/s in the postive x direction.
A) Draw the path of the proton.
B) Find the change in the y direction of the proton.
I HOPE THE LENGTH OF PLATES YOU HAVE MENTIONED IS 0.2 m NOT 200 m
Because, due to electric field due to parallel plates the proton will experience a force in y-direction :
Fy = qp * Ey = mp * ay
where, qp and mp are the charges and masses of the proton respectively and ay is the acceleration in ...
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