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# Magnitude of velocity of a electron

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An electron e= 1.6*10^-19C, m= 9.1*10^-31kg is accelerated through a potential difference of 2kV. It then passes into a magnetic field perpendicular to its path, where it moves in a circular arc of diameter 0.36m.

1.) What is the magnitude of the velocity of the electron in a magnetic field?

2.) What is the magnitude of the magnetic field?

3.) What is the frequency of the electron's motion in the magnetic field?

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This solution provides step-by-step calculations for finding the magnitude of velocity of an electron.

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Dear student,

When this electron is accelerated first in the electric field, the Electro static PE converts into KE.

using ...

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