Purchase Solution

Magnitude of velocity of a electron

Not what you're looking for?

Ask Custom Question

An electron e= 1.6*10^-19C, m= 9.1*10^-31kg is accelerated through a potential difference of 2kV. It then passes into a magnetic field perpendicular to its path, where it moves in a circular arc of diameter 0.36m.

1.) What is the magnitude of the velocity of the electron in a magnetic field?

2.) What is the magnitude of the magnetic field?

3.) What is the frequency of the electron's motion in the magnetic field?

Purchase this Solution

Solution Summary

This solution provides step-by-step calculations for finding the magnitude of velocity of an electron.

Solution Preview

Dear student,

When this electron is accelerated first in the electric field, the Electro static PE converts into KE.

using ...

Purchase this Solution


Free BrainMass Quizzes
Basic Physics

This quiz will test your knowledge about basic Physics.

Intro to the Physics Waves

Some short-answer questions involving the basic vocabulary of string, sound, and water waves.

Classical Mechanics

This quiz is designed to test and improve your knowledge on Classical Mechanics.

The Moon

Test your knowledge of moon phases and movement.

Variables in Science Experiments

How well do you understand variables? Test your knowledge of independent (manipulated), dependent (responding), and controlled variables with this 10 question quiz.