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Final paramtrs of proton under const acceleration

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A proton (m=1.67*10^-27kg) is being accelerated along a straight line at 3.6*10^5 m/sec ^2 in a machine. If the proton has an inital speed of 2.4*10^7 m/sec:

What is the final velocity after traveling for 2 sec?
What is the force acting on the proton?
What is the increase in its kinectic energy?

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Acceleration of a non relativistic proton-example problem:

A proton (m=1.67*10^-27kg) is being accelerated along a straight line at 3.6*10^5 m/sec ^2 in a machine. If the proton has an initial speed of 2.4*10^7 m/sec.

What is the final velocity after travelling for 2 sec?

What is the force acting on the proton?

What is the increase in its kinetic energy?

Solution:

So mass m = 1.67*10^-27 kg

Constant acceleration ...

Solution Summary

A proton (m=1.67*10^-27kg) is being accelerated along a straight line at 3.6*10^5 m/sec ^2 in a machine, the proton has an inital speed of 2.4*10^7 m/sec: Using equations from linear kinematics (non relativistic case) the final velocity of the proton is determined. From this the force acting on the proton is determined as is its increase in linetic energy

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