In a problem, I'm supposed to calculate the number of Uranium-235 nuclei in 10^4 Kg of Uranium. The answer book gives
Number of U-235 nuclei = (10^4)*(1000/238)(6*10^23)(0.02) = 5*10^26
I don't know where the factor 6*10^23 and (1000/238) come from. The 0.02 come from the fact that 2% of Uranium is U-235 and the rest is U-238. 10^4 is the mass. Is the number 238 somehow associated with U-238? Could you please explain, why this calculation includes (1000/238) and 6*10^23? Thank you.© BrainMass Inc. brainmass.com August 21, 2018, 7:10 pm ad1c9bdddf
Molecular weight of U-238 = 238 Grams
Hence, Number of ...
The solution provides a calculation to determine the number of Uranium-235 nuclei.