Calculating Atomic Masses After Fission Collision

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  Let the masses of the particles be m1 and m2 and their initial velocities (along line joining) are u1 and u2 respectively (u1 must be > u2 for collision), and after collision moving with velocities v1 and v2 respectively (v2 >v1 ; separation) 1) If

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  Hence, 235U92 + 1n0 = 236U92 = 121Ag47 + 4 1n0 + xEy where E is the unknown fission fragment with an atomic mass of x Hence, x + 4 + 121 = 236 or x = 111 From the periodic table, the element that corresponds to atomic mass 111 is Cadmium.

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  The atomic bomb dropped on Hiroshima on August 6, 1945, released 5 x 10^13 J of energy equivalent to that from 12,000 tons of TNT. (Assume that a typical 235U fission releases approximately 200 MeV of energy.)

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  So after the first one, 100 mg will remain. After the second, 50 mg. And at noon we will have 25 mg of Fl-18. i. only fusion requires high temperatures to initiate ii. fusion creates less radiation than fission iii.

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  Amount of nuclear waste will be very less in comparison to fission reactor 2. Fusions plants are not subjected to meltdown. In fission reactors the nuclear core remains hot even months after the fission process has stopped.

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