Share
Explore BrainMass

Electrical Energy: Center Temperature and Maximum Temperature of a Wall

Please see the attached file for the fully formatted problem(s).

Find center temperature and maximum temperature in the wall.

Given that in problem
Radius of wire r = 0.001268m
Length of wire L= 0.9m
Average conductivity k = 22.5 W/m.K
Resistance R = 0.126 ohms
Current = 200A
Wall temperature Twall = 422.1K

Attachments

Solution Preview

Please see the attached file(s) for the complete solution.
Thanks for using BrainMass.

Assignment no.5
Problem5.1

1. Basic concept of this assignment is related to
(a) current
(b) Resistance
(c) Volumetric heat generation
In this type of problem we use simple Ohms law

Q = I2*R
Where R = resistance

Solution:
Given that in problem
Radius of wire r = 0.001268m
Length of wire L= 0.9m
Average conductivity k = 22.5 W/m.K
Resistance R = 0.126 ohms
Current = 200A
Wall temperature Twall = 422.1K
So total energy generation rate qg = I2*R
= (200)2*0.126
...

Solution Summary

Center temperature and maximum temperature of a Wall are calculated from given data is analyzed. The solution is detailed and well presented.

$2.19