Electrical Energy: Center Temperature and Maximum Temperature of a Wall

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Assignment no.5
Problem5.1

1. Basic concept of this assignment is related to
(a) current
(b) Resistance
(c) Volumetric heat generation
In this type of problem we use simple Ohms law

Q = I2*R
Where R = resistance

Solution:
Given that in problem
Radius of wire r = 0.001268m
Length of wire L= 0.9m
Average conductivity k = 22.5 W/m.K
Resistance R = 0.126 ohms
Current = 200A
Wall temperature Twall = 422.1K
So total energy generation rate qg = I2*R
= (200)2*0.126
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