Electricity: Power dissipated by a resistor
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The voltage drop across an electrical resistor is 10 volts and the current through it is 1 ampere. The total heat capacity of the resistor is 20 J/K, and heat dissipated from the resistor to the surrounding air according to the relation:
Q = -h(T-Tam)
Where Tam is the ambient air temperature, 25 deg.C; T is the temperature of the resistor; and h, the heat transfer coefficient, is equal to 0.2 J/(K s). Compute the steady state temperature of the resistor, that is, the temperature of the resistor when the energy loss from the resistor is just equal to the electrical energy input.
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Power dissipated by a resistor is examined.
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Heat generated by the resistor per sec = VI = 10 watts
Rate of heat dissipation by the ...
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