Explore BrainMass
Share

Current Through Series of Resistors

This content was STOLEN from BrainMass.com - View the original, and get the already-completed solution here!

Three resistors having resistances of 1.20ohms , 2.60ohms , and 5.00 ohms are connected in series to a 26.0 V battery that has negligible internal resistance.

1) Find the equivalent resistance of the combination

2) Find the current in through 1.60, 2.50, and 5.00ohms resistors.

3) Find the total current through the battery.

4) Find the power dissipated in 1.60, 2.50, and 5.00ohms resistors

5) Which resistor dissipates the most power: the one with the greatest resistance or the least resistance? and why?

© BrainMass Inc. brainmass.com October 24, 2018, 11:50 pm ad1c9bdddf
https://brainmass.com/physics/power/current-through-series-resistors-206909

Solution Preview

1.

The resistors are connected in series.
Therefore the total equivalent resistance is the sum of the individual resistors:

Req = R1+R2+R3 = 1.2 + 2.6 + 5.0 = 8,8 ohms.

2. 3.

In a series connection, conservation of charge dictates that the current (charge per unit time) through all the elements must be the same.

Since all the resistors are connected in series, the current ...

Solution Summary

Solution to the current through series of resistors is given.

$2.19
See Also This Related BrainMass Solution

Current in series circuit

A 12 volt battery and two resistors are wired in series. The resistor values are 80 Ohms and 40 Ohms.

a. What is the current through the resistors?
b. What is the voltage across the 80 ohm resistor?
c. What is the voltage across the 40 ohm resistor?

View Full Posting Details