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    A 12 volt battery and two resistors are wired in series. The resistor values are 80 Ohms and 40 Ohms.

    a. What is the current through the resistors?
    b. What is the voltage across the 80 ohm resistor?
    c. What is the voltage across the 40 ohm resistor?

    © BrainMass Inc. brainmass.com December 24, 2021, 9:03 pm ad1c9bdddf
    https://brainmass.com/physics/ohms-law/current-series-circuit-339321

    SOLUTION This solution is FREE courtesy of BrainMass!

    a. Current through the resistors = I = V/R = 12V /(80+ 40)ohm = 12V/(120 ohm) = 0.1 A

    In a series circuit, the current that flows through the two resistors is same, so we need to apply Ohm's law here.

    b. Since the current through 80 ohms resistor is 0.1 amps, the voltage across it is:
    V_1 = I * R1 = 0.1A * 80 ohm = 8 V

    c. Similarly, the current through 40 ohms resistor is also 0.1 amps, so the voltage across it is:
    V_2 = I * R2 = 0.1A * 40 ohm = 4 V

    We can also verify that the total voltage across the two resistors is 12 V:
    V_1 + V_2 = 8 + 4 = 12, which is equal to the battery voltage.

    This content was COPIED from BrainMass.com - View the original, and get the already-completed solution here!

    © BrainMass Inc. brainmass.com December 24, 2021, 9:03 pm ad1c9bdddf>
    https://brainmass.com/physics/ohms-law/current-series-circuit-339321

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