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    The Mass Defect of the Nucleus and Nuclear Binding Energy

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    For bismuth 209/83 Bi (atomic mass = 208.980374 u) obtain each of the following:
    (a) The mass defect in atomic mass units
    (b) the binding energy (in MeV)
    (c) the binding energy per nucleon (in MeV)

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    Solution Preview

    Bismuth: p = Number of protons = Z = 83, n = Number of neutrons = A - Z = 209 - 83 = 126

    Actual mass of a Bismuth nucleus = Mass of 83 ...

    Solution Summary

    Bismuth: p = Number of protons = Z = 83, n = Number of neutrons = A - Z = 209 - 83 = 126

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