Purchase Solution

Energy required to separate nucleus

Not what you're looking for?

Ask Custom Question

The nucleus 6C12 consists of six protons and six neutrons held in close association by strong nuclear forces. The atomic rest masses are

6C12: 12.000000u
1H1: 1.007825u
n: 1.008665u

in terms of the atomic mass unit u = 1.66 x 10^-27 kg. How much energy would be required to separate a 6C12 nucleus into its constituent protons and neutrons?

This problem has me totally confused. Am I using the formula for Relativistic kinetic energy:

K = (mc2/√1 - v2/c2) - mc2

or for rest energy:

E0 = mc2

or neither? How do I do this problem?

See attached file for full problem description.

Attachments
Purchase this Solution
Solution Summary

The solution explains how to calculate the energy required to separate the nucleus that is held together by strong nuclear forces.

Solution Preview

The nucleus 6C12 consists of six protons and six neutrons held in close association by strong nuclear forces. The atomic rest masses are

6C12: 12.000000u
1H1: ...

Purchase this Solution
Free BrainMass Quizzes
The Moon

Test your knowledge of moon phases and movement.

Basic Physics

This quiz will test your knowledge about basic Physics.

Intro to the Physics Waves

Some short-answer questions involving the basic vocabulary of string, sound, and water waves.

Classical Mechanics

This quiz is designed to test and improve your knowledge on Classical Mechanics.

Variables in Science Experiments

How well do you understand variables? Test your knowledge of independent (manipulated), dependent (responding), and controlled variables with this 10 question quiz.

View More Free Quizzes
Related BrainMass Solutions

  • Physics - Atomic and Nuclear

    217025 Physics - Atomic and Nuclear (a)Energy is required to separate a nucleus into its constituent nucleons. This energy is the total binding energy of the nucleus.

  • Nuclear fusion vs fission

    However, the release of energy once the two nuclei come together is greater than the energy required to fuse them in the first place. Therefore, since you get more energy out of the process than you put into it, it would be awesome if it could work.

  • Explain radioactivity in terms of an unstable nucleus.

    (Because the mass of any nucleus is less than the sum of the separate masses of its protons and neutrons, the missing mass is called the mass defect.) The mass defect in turn determines the binding energy.

  • How many fusions per second would be required to produce one (1) watt of power?

    119319 How many fusions per second would be required Through certain techniques, a deuterium nucleus and a tritium nucleus can be made to fuse at very low kinetic energy to form an α - particle and a neutron.

  • Process that Powers the Sun

    The Strong force binds the quarks in the helium nucleus strongly together. The total energy of the quarks when bound together in the helium nucleus is less than when the quarks are bound in four separate protons.

  • Calculating Nuclear Decay

    i) Determine the energy required to remove a proton from a 12C nucleus (in MeV) - For this one, I know that this is not alpha, beta, or gamma decay, so I don't know how I'm supposed to do it. 6C12  5N11 + 1p1 Mass of one nucleus of C-12 = 12.0000

  • Number of Collisions in a Nuclear Reactor

    Extend this calculation to find out how many such collisions are required to reduce the neutron kinetic energy to 0.025 eV. Hello, Please find the answer to this question in the attached file. Thank you.

  • First Ionization Energy

    The farther these electrons are, the less held together they are by the nucleus, the easier it is to pull off, the less energy is required to ionize the atom, thus the smaller the ionization energy.

  • Nuclear Fusion Statements

    A very high temperature (of the order of lacs of deg C) is required to form plasma, not easy. 4. True. Easy to get lighter nuclei. 5. False. Binding energy per nucleon increases with mass number for light nucleus.

View More Related Solutions