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Radioactive Decay Series

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A radioactive decay series that begins with 237/93 Np ends with formation of the stable isotope 209/83 Bi. How many alpha particle emissions and how many beta particle emissions are involved in the sequence of radioactive decay?

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Solution Preview

The nuclear equation is:

237/93 Np --> 209/83Bi + x * 4/2 He + y * 0/-1 e

where 4/2 He is an alpha particle, ...

Solution Summary

The solution provides clear, concise steps to finding the number of alpha and beta emissions of a radioactive decay series.

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