A radioactive decay series that begins with 237/93 Np ends with formation of the stable isotope 209/83 Bi. How many alpha particle emissions and how many beta particle emissions are involved in the sequence of radioactive decay?
The nuclear equation is:
237/93 Np --> 209/83Bi + x * 4/2 He + y * 0/-1 e
where 4/2 He is an alpha particle, ...
The solution provides clear, concise steps to finding the number of alpha and beta emissions of a radioactive decay series.