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Electrical Potential of two point charges

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Magnitude of Electrical Potential. See attached file for full problem description.

23. An alpha particle, starting from rest, acquired a speed of 1.38 x 10^5 m/s whiles moving through an electric potential difference.
a. The magnitude of the electric potential was
b. the final energy of the alpha particle, in electron volts, was

22. A charge of 5.0 nC is placed at the origin and another charge of -9.4 nC is placed at x = 26.0 cm.
a. where on the x-axis is the resulting electric potential is equal to zero volts

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Solution Summary

It calculates the resulting electric potential of two point charges. It also investigates the movement of an alpha particle through an electric potential difference. The solution is detailed and was rated '5/5' by the student who posted the questions.

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Determining Electric Potential Created from Two Point Charges

Two point charges, q1= 2.00 nC and q2= -6.80 nC, are 0.100 m apart. Point A is midway between them; point B is 0.080 m from q1 and 0.060 m from q2 (see the attachment). Take the electric potential to be zero at infinity.

Find the potential at point A.

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Find the work done by the electric field on a charge of 2.80 nC that travels from point B to point A.

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