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Clay target hit by bullet

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A 0.250 kg skeet (clay target) is fired at an angle of alpha = 32.6o to the horizon with a speed of v0 = 29.3 m/s, as seen in figure below.

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When it reaches the maximum height, it is hit from below by a 15 g pellet traveling vertically upward at a speed of v = 186 m/s. The pellet is embedded in the skeet. How much higher did the skeet go up?

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At the moment the bullet hit, the skeet has zero vertical velocity, therefore the vertical momentum of them continuing together is

p_y = m_bullet*v = 0.015 kg * 186 m/s = ...

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