... 5. If two planes are parallel, then a normal vector to one is a normal vector to the other as well: The plane M' is defined by the vectors u and v ...

... deemed to be perpendicular to the plane in which ... second vector, the direction of the product vector is deemed ... scalar (dot) product of two vectors performed in ...

... c) we know that two vectors u and v are perpendicular, if uv = 0. ... with ||u|| = 2 => u12 + u22 + u32 = 4. now if the vector lies in yz-plane, we have u1=0. ...

... of the proton r = the unit vector from charge to the point of interest (the dot). Since both of this vectors are on the xy plane, the cross product of them ...

... of radius R and lies in the xy plane with its ... zero because it is the cross product of two parallel vectors. ... You then draw a vector from the center of the disk ...

... so that when it hits the ground, it is 4410 m directly below the plane! ... the vector from the axis of rotation to the application point and the force vector. ...

... this circle of curvature must be on the osculating plane. ... I think you are familiar with differentiating vectors, and calculate ...vector r(t) = ti + 1/2 t^2 j + 1 ...

... 2 2 2 2 unit vectors u1 = ( − ,0, ) and u 2 = ( ,0,− ). 2 2 2 ... k 4 3 1 = = i+ j+ k Then the unit vector is || v ... 1 y + 2 z − 6 = = 1 2 3 On xy-plane, z = 0 ...

... is equal to the cross product of these two vectors: j ik v ... that the dot product of this vector with any vector whose end lies in the plane will equal ...